mysql 获取当天发布的信息的语句
2026-01-17 15:01:06 作者:用户投稿
复制代码 代码如下:
SELECT * FROM `p8_memberdata` where regdate BETWEEN (UNIX_TIMESTAMP(NOW())-86440) AND NOW()
SELECT * FROM `p8_memberdata` WHERE DATE_FORMAT(FROM_UNIXTIME(regdate),'%Y-%m-%d')= DATE_FORMAT(NOW(),'%Y-%m-%d') order by uid desc
第一条最好显示过去24小时过去1周等
第二条获得当天信息
SELECT * FROM `p8_memberdata` where regdate BETWEEN (UNIX_TIMESTAMP(NOW())-86440) AND NOW()
SELECT * FROM `p8_memberdata` WHERE DATE_FORMAT(FROM_UNIXTIME(regdate),'%Y-%m-%d')= DATE_FORMAT(NOW(),'%Y-%m-%d') order by uid desc
第一条最好显示过去24小时过去1周等
第二条获得当天信息
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